Optimal. Leaf size=22 \[ \text{Unintegrable}\left (\frac{(a+b \tan (e+f x))^2}{(c+d x)^2},x\right ) \]
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Rubi [A] time = 0.051245, antiderivative size = 0, normalized size of antiderivative = 0., number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0., Rules used = {} \[ \int \frac{(a+b \tan (e+f x))^2}{(c+d x)^2} \, dx \]
Verification is Not applicable to the result.
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Rubi steps
\begin{align*} \int \frac{(a+b \tan (e+f x))^2}{(c+d x)^2} \, dx &=\int \frac{(a+b \tan (e+f x))^2}{(c+d x)^2} \, dx\\ \end{align*}
Mathematica [A] time = 14.3644, size = 0, normalized size = 0. \[ \int \frac{(a+b \tan (e+f x))^2}{(c+d x)^2} \, dx \]
Verification is Not applicable to the result.
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Maple [A] time = 1.779, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( a+b\tan \left ( fx+e \right ) \right ) ^{2}}{ \left ( dx+c \right ) ^{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{{\left (a^{2} - b^{2}\right )} d f x - 2 \, b^{2} d \sin \left (2 \, f x + 2 \, e\right ) +{\left (a^{2} - b^{2}\right )} c f +{\left ({\left (a^{2} - b^{2}\right )} d f x +{\left (a^{2} - b^{2}\right )} c f\right )} \cos \left (2 \, f x + 2 \, e\right )^{2} +{\left ({\left (a^{2} - b^{2}\right )} d f x +{\left (a^{2} - b^{2}\right )} c f\right )} \sin \left (2 \, f x + 2 \, e\right )^{2} + 2 \,{\left ({\left (a^{2} - b^{2}\right )} d f x +{\left (a^{2} - b^{2}\right )} c f\right )} \cos \left (2 \, f x + 2 \, e\right ) - 4 \,{\left (d^{3} f x^{2} + 2 \, c d^{2} f x + c^{2} d f +{\left (d^{3} f x^{2} + 2 \, c d^{2} f x + c^{2} d f\right )} \cos \left (2 \, f x + 2 \, e\right )^{2} +{\left (d^{3} f x^{2} + 2 \, c d^{2} f x + c^{2} d f\right )} \sin \left (2 \, f x + 2 \, e\right )^{2} + 2 \,{\left (d^{3} f x^{2} + 2 \, c d^{2} f x + c^{2} d f\right )} \cos \left (2 \, f x + 2 \, e\right )\right )} \int \frac{{\left (a b d f x + a b c f + b^{2} d\right )} \sin \left (2 \, f x + 2 \, e\right )}{d^{3} f x^{3} + 3 \, c d^{2} f x^{2} + 3 \, c^{2} d f x + c^{3} f +{\left (d^{3} f x^{3} + 3 \, c d^{2} f x^{2} + 3 \, c^{2} d f x + c^{3} f\right )} \cos \left (2 \, f x + 2 \, e\right )^{2} +{\left (d^{3} f x^{3} + 3 \, c d^{2} f x^{2} + 3 \, c^{2} d f x + c^{3} f\right )} \sin \left (2 \, f x + 2 \, e\right )^{2} + 2 \,{\left (d^{3} f x^{3} + 3 \, c d^{2} f x^{2} + 3 \, c^{2} d f x + c^{3} f\right )} \cos \left (2 \, f x + 2 \, e\right )}\,{d x}}{d^{3} f x^{2} + 2 \, c d^{2} f x + c^{2} d f +{\left (d^{3} f x^{2} + 2 \, c d^{2} f x + c^{2} d f\right )} \cos \left (2 \, f x + 2 \, e\right )^{2} +{\left (d^{3} f x^{2} + 2 \, c d^{2} f x + c^{2} d f\right )} \sin \left (2 \, f x + 2 \, e\right )^{2} + 2 \,{\left (d^{3} f x^{2} + 2 \, c d^{2} f x + c^{2} d f\right )} \cos \left (2 \, f x + 2 \, e\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{b^{2} \tan \left (f x + e\right )^{2} + 2 \, a b \tan \left (f x + e\right ) + a^{2}}{d^{2} x^{2} + 2 \, c d x + c^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (a + b \tan{\left (e + f x \right )}\right )^{2}}{\left (c + d x\right )^{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \tan \left (f x + e\right ) + a\right )}^{2}}{{\left (d x + c\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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